8b^2+80b=-128

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Solution for 8b^2+80b=-128 equation:


Simplifying
8b2 + 80b = -128

Reorder the terms:
80b + 8b2 = -128

Solving
80b + 8b2 = -128

Solving for variable 'b'.

Reorder the terms:
128 + 80b + 8b2 = -128 + 128

Combine like terms: -128 + 128 = 0
128 + 80b + 8b2 = 0

Factor out the Greatest Common Factor (GCF), '8'.
8(16 + 10b + b2) = 0

Factor a trinomial.
8((8 + b)(2 + b)) = 0

Ignore the factor 8.

Subproblem 1

Set the factor '(8 + b)' equal to zero and attempt to solve: Simplifying 8 + b = 0 Solving 8 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + b = 0 + -8 Combine like terms: 8 + -8 = 0 0 + b = 0 + -8 b = 0 + -8 Combine like terms: 0 + -8 = -8 b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(2 + b)' equal to zero and attempt to solve: Simplifying 2 + b = 0 Solving 2 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + b = 0 + -2 b = 0 + -2 Combine like terms: 0 + -2 = -2 b = -2 Simplifying b = -2

Solution

b = {-8, -2}

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